How to? Timeout exception for function

#1

Is there a way to run a function that, if it takes longer than time t to run, it times out?

Looking for something along the lines of

try {
…
func();
…
} catch (e:Timeout) {
// timed out running try block
}

I simply can’t find any way to do this, and would really like to know if anyone’s been able to?

#2

Start the timer inside func()?
And then return or throw the Timeout.
I assume of course you can alter func…

#3

I want to be able to do this with any given function, without altering the function itself.

#4

Hmm. Then I guess you’ll have to start a new process, then you can just kill it any time you like…

#5

Could you elaborate?

I don’t believe there’s a way to kill a running process at any time.

#6

http://api.haxe.org/sys/io/Process.html

So, do a var p = new Process(...) and then p.kill() it.

#7

I’ve seen that - but that’s specifically an external process, no? You can’t call a haxe function directly using new Process can you?

#8

Nope. That’s an entirely new process.
Maybe there are other ways, but I don’t know of any…

#9

I think my question boils down to, is there a way to interrupt/kill a running function in haxe from an external function?

#10

I think it would only work if you had a function that could work as multiple iterations (and you stop iterating when some condition changes), another option may be if it works in a different thread, though I do not how stable it would be if you are allowed to kill the thread

#11

You can use deferred/promises ( https://github.com/jdonaldson/promhx )

With your function call also start a haxe.timer.delay - if the timer is reached and the promise wasn’t resolved yet, reject the promise

( that doesn’t kill the running function though, but you have essentially a timeout handler. if the function you called exposes cancel methods, call them within the timeout function as well )